How many moles of NaOH were used in the titration?

How many moles of NaOH were used in the titration?

Since 30 ml (or 0.03 liters) of NaOH was used for the titration, 0.03 liters · 0.1 moles/liter = 0.003 moles of NaOH was used to titrate the HCl. Since the mole ratio is 1:1, the same number of moles (0.003) of HCl must have been titrated.

How do you find moles of NaOH?

Converting Mass to Number of Moles How many moles of NaOH are present in 90 g of NaOH? Since the molar mass of NaOH is 40 g/mol, we can divide the 90 g of NaOH by the molar mass (40 g/mol) to find the moles of NaOH. This the same as multiplying by the reciprocal of 40 g/mol.

How many moles of NaOH are required to neutralize HCl?

A 1:1 mole ratio basically means that the reaction consumes equal numbers of moles of sodium hydroxide and of hydrochloric acid. In other words, for every 1 mole of sodium hydroxide that takes part in the reaction, you need 1 mole of hydrochloric acid to neutralize it.

What is the number of moles of NaOH needed to reach the equivalence point?

A mole is equal to 6.022 x 1023 molecules.) By doing the titration and making a plot of the volume of NaOH added versus the resulting pH of the solution, we find that the equivalence point occurs at 0.04398 L of NaOH.

What is one mole of NaOH?

The molar mass tells you the mass of exactly one mole of a given substance. In this case, sodium hydroxide has a molar mass of 39.997 g mol−1 , which implies that one mole of sodium hydroxide has a mass of 39.997 g .

Is NaOH an acid or base?

Now let’s look at lye, a strong base with the chemical formula NaOH (sodium hydroxide). If we add NaOH to water, it dissociates into Na+ and OH-. The sodiums don’t do anything important, but the hydroxyls make the solution more basic.

How do you find moles to neutralize?

Solving an Acid-Base Neutralization Problem

1. Step 1: Calculate the number of moles of OH-. Molarity = moles/volume. moles = Molarity x Volume. moles OH- = 0.02 M/100 milliliters.
2. Step 2: Calculate the Volume of HCl needed. Molarity = moles/volume. Volume = moles/Molarity. Volume = moles H+/0.075 Molarity.

How do you find the moles of NaOH in a titration?

Step 1: Calculate the amount of sodium hydroxide in moles

1. Amount of solute in mol = concentration in mol/dm 3 × volume in dm 3
2. Amount of sodium hydroxide = 0.100 × 0.0250.
3. = 0.00250 mol.
4. The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H 2O(l)
5. So the mole ratio NaOH:HCl is 1:1.

How many moles are needed to neutralize?

Titrations. When hydrochloric acid is reacted with sodium hydroxide, an acid/base mole ratio of 1:1 is required for full neutralization. If instead the hydrochloric acid were reacted with barium hydroxide, the mole ratio would be 2:1. Two moles of HCl are required to completely neutralize one mole of Ba(OH)2.